The classic: legs 3 and 4
a = 3, b = 43² + 4² = 9 + 16 = 25, and √25 = 5 exactly. This is the 3-4-5 triangle, the smallest one with three whole sides, and it is worth recognising on sight - as are its multiples 6-8-10 and 9-12-15.
Two sides on a drawn triangle give the third, exactly - radicals included.
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The Coddy math course teaches the method itself - you work each step on an interactive board and get told exactly where a move went wrong.
On a right triangle, and only on a right triangle, a² + b² = c², where c is the hypotenuse - the side opposite the right angle and always the longest of the three. The statement is about AREAS: build a square on each of the two shorter sides and their combined area is exactly the area of the square built on the longest one. That is why everything gets squared and why the answer needs a square root at the end.
Which way the arithmetic runs depends on which side is missing, and that is where most mistakes live. Looking for the hypotenuse, you ADD the two squares. Looking for a leg, you SUBTRACT: a² = c² − b², because the hypotenuse's square is the total and the known leg's square is part of it. Adding when you should subtract gives an answer bigger than the hypotenuse, which is impossible - a useful check.
The answers here are exact. The hypotenuse of a triangle with legs 2 and 3 is √13, and √13 is what this page reports - with 3.6056 beside it, labelled as the rounding it is. √20 is simplified to 2√5 rather than left as it stands, and a triangle whose three sides come out whole is flagged as the Pythagorean triple it is.
It is the side opposite the right angle, and the longest of the three. Getting this wrong makes every step afterwards wrong, so label it before you calculate anything.
Missing hypotenuse: add the squares of the two legs. Missing leg: subtract the known leg's square from the hypotenuse's square.
Square first, then add or subtract. Squaring after adding - (a + b)² - is a different and much larger number.
That undoes the squaring and gives the side itself. If it does not come out whole, simplify the radical rather than reaching for a decimal: √20 is 2√5.
The hypotenuse must be longer than either leg and shorter than their sum. If your answer breaks either rule, the addition and subtraction got swapped.
The triples worth memorising, and what happens when the answer is not whole. The exact column is the answer; the decimal is a rounding of it.
| a | b | c | Exact | Decimal |
|---|---|---|---|---|
| 3 | 4 | 5 | 5 | 5 |
| 6 | 8 | 10 | 10 | 10 |
| 5 | 12 | 13 | 13 | 13 |
| 8 | 15 | 17 | 17 | 17 |
| 7 | 24 | 25 | 25 | 25 |
| 1 | 1 | √2 | √2 | 1.4142 |
| 2 | 3 | √13 | √13 | 3.6056 |
| 2 | 4 | 2√5 | 2√5 | 4.4721 |
a = 3, b = 43² + 4² = 9 + 16 = 25, and √25 = 5 exactly. This is the 3-4-5 triangle, the smallest one with three whole sides, and it is worth recognising on sight - as are its multiples 6-8-10 and 9-12-15.
a = 2, b = 34 + 9 = 13, so the hypotenuse is √13. That is the answer - 3.6056 is a rounding of it, and squaring 3.6056 gives 12.9999… rather than 13. Most right triangles are like this one; the whole-number cases are the exception.
a = 2, b = 44 + 16 = 20, and √20 is not left as it stands: 20 = 4 · 5, and the 4 comes out of the root as a 2, giving 2√5. Same number, and the form every marking scheme expects.
b = 4, c = 5Rearrange first: a² = c² − b² = 25 − 16 = 9, so a = 3. Adding instead would have given √41 ≈ 6.4, which is longer than the hypotenuse - impossible, and the check that catches this mistake immediately.
a = 3/2, b = 29/4 + 4 = 25/4, and the square root of 25/4 is 5/2 exactly. Fractions stay fractions all the way through, which is why the answer is 5/2 rather than 2.5 - though both are the same number here.
On a right triangle, a² + b² = c², where a and b are the two shorter sides (the legs) and c is the hypotenuse opposite the right angle. Read as areas: the squares built on the two legs have exactly the combined area of the square built on the hypotenuse.
Square both legs, add them, and take the square root: c = √(a² + b²). For legs 3 and 4 that is √25 = 5. If the root does not come out whole, keep it as a simplified radical - √20 becomes 2√5.
Subtract, do not add: a² = c² − b², so a = √(c² − b²). With a hypotenuse of 5 and a leg of 4 that is √(25 − 16) = 3. This is the case that goes wrong most often, and the check is that a leg must always be shorter than the hypotenuse.
Three whole numbers that satisfy the theorem: 3-4-5, 5-12-13, 8-15-17, 7-24-25. Any multiple of a triple is also a triple, so 6-8-10 and 9-12-15 come free with 3-4-5. Most right triangles are NOT triples, which is why irrational answers are the norm.
No - only on right triangles. For any other triangle the general statement is the law of cosines, c² = a² + b² − 2ab·cos(C), which reduces to the Pythagorean theorem exactly when C is 90° and its cosine is zero.
Because a radical is the exact answer and a decimal is a rounding of it. √13 squared is 13 on the nose; 3.61 squared is 13.0321. In a multi-step problem that difference compounds, and most marking schemes want the exact form anyway.
Test the theorem on the three sides you have: if a² + b² equals c² exactly, with c the longest side, the triangle has a right angle. If the left side is bigger the angle is acute, and if smaller it is obtuse - which is the converse of the theorem and a genuinely useful check.
Yes, and both stay exact. Legs of 3/2 and 2 give a hypotenuse of exactly 5/2, and a decimal input is read as the exact fraction it names rather than as a floating-point approximation of it.