Menu

1 + cot²x = csc²x

Part of the Trig Identities section of Coddy's Trigonometry journey. Lesson 11 of 52.

Divide sin(x)² + cos(x)² = 1 by sin(x)² instead. The first term becomes 1, the second cot(x)², and the right side 1/sin(x)², which is csc(x)²:

1 + cot(x)² = csc(x)²

It holds wherever sin x is not 0. So there are three Pythagorean identities, one for each pair: sine and cosine, tangent and secant, cotangent and cosecant. The 1 always sits with tan² and cot², never with sec² or csc².

Take csc(x)² - cot(x)². Replace csc(x)² with 1 + cot(x)² and it reads 1 + cot(x)² - cot(x)². The cotangent squares cancel, and 1 is left.

challenge icon

Challenge

Show that (csc(x)² - 1)/cot(x) equals cot(x): rewrite it until the board reads cot(x). Then press Check.

Try it yourself

(csc(x)^2 - 1)/cot(x)

Simplify the expression

quiz iconTest yourself

This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Trig Identities