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Proofs That Go Wrong

Part of the Trig Identities section of Coddy's Trigonometry journey. Lesson 20 of 48.

Four moves look like algebra and are not:

Cancelling a term of a sum. In sin⁡(x)+cos⁡(x)sin⁡(x)\frac{\sin\left(x\right)+\cos\left(x\right)}{\sin\left(x\right)} the sin x cannot be crossed out: it is a term on top, not a factor. Split the fraction instead: 1+cos⁡(x)sin⁡(x)1+\frac{\cos\left(x\right)}{\sin\left(x\right)}.

Splitting a function. sin⁡(2x)\sin\left(2x\right) is not 2sin⁡(x)2\sin\left(x\right), and sin⁡(x+y)\sin\left(x+y\right) is not sin⁡(x)+sin⁡(y)\sin\left(x\right)+\sin\left(y\right): a function is not a number to multiply out.

Reading the square as the angle. sin⁡(x)2{\sin\left(x\right)}^{2} squares the value, sin⁡(x2)\sin\left({x}^{2}\right) squares the angle.

Dividing by something that can be 0. Dividing by sin x is not allowed where sin x is 0; factor instead.

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Challenge

Prove that (1−sin⁡(x)2)tan⁡(x)2\left(1-{\sin\left(x\right)}^{2}\right){\tan\left(x\right)}^{2} equals sin⁡(x)2{\sin\left(x\right)}^{2}: rewrite it until the board reads sin⁡(x)2{\sin\left(x\right)}^{2}. Then press Check.

Try it yourself

(1−sin⁡2x)tan⁡2x\left(1-\sin^{2} x\right)\tan^{2} x

Rewrite as sin⁡2x\sin^{2} x

All lessons in Trig Identities