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Factor First

Part of the Trig Identities section of Coddy's Trigonometry journey. Lesson 18 of 48.

When every term shares a trig factor, take it out: the bracket left behind is often an identity. Prove sin⁡(x)3+sin⁡(x)cos⁡(x)2=sin⁡(x){\sin\left(x\right)}^{3}+\sin\left(x\right){\cos\left(x\right)}^{2} = \sin\left(x\right). Both terms hold a sin x, so Take out the common trig factor: sin⁡(x)(sin⁡(x)2+cos⁡(x)2)\sin\left(x\right)\left({\sin\left(x\right)}^{2}+{\cos\left(x\right)}^{2}\right). The bracket is 1, and sin x times 1 is sin x.

Factoring keeps the value; dividing does not. Dividing the expression by sin x would change what it equals, and lose the angles where sin x is 0. Take the factor out and keep it on the line.

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Challenge

Prove that cos⁡(x)2sec⁡(x)2−tan⁡(x)2cos⁡(x)2{\cos\left(x\right)}^{2}{\sec\left(x\right)}^{2}-{\tan\left(x\right)}^{2}{\cos\left(x\right)}^{2} equals cos⁡(x)2{\cos\left(x\right)}^{2}: rewrite it until the board reads cos⁡(x)2{\cos\left(x\right)}^{2}. Then press Check.

Try it yourself

cos⁡2xsec⁡2x−tan⁡2xcos⁡2x\cos^{2} x \sec^{2} x-\tan^{2} x \cos^{2} x

Rewrite as cos⁡2x\cos^{2} x

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Trig Identities