Two Denominators
Part of the Fundamentals section of Coddy's Algebra journey. Lesson 34 of 61.
The equation x/2 + x/3 = 10 says that half a number plus a third of it is 10. It has two denominators, 2 and 3. To clear both, multiply every term by a number that both 2 and 3 divide into. The smallest such number is their least common multiple, which is 6:
6 × x/2 + 6 × x/3 = 6 × 10
3x + 2x = 60
5x = 60
x = 12
One multiplication by 6 removed both fractions. Check the answer: 12/2 + 12/3 = 6 + 4 = 10.
Any common multiple of the denominators clears the fractions, as long as it is not zero. The least common multiple keeps the numbers small. You can also add the two fractions first: x/2 + x/3 is 5/6 x, so the equation becomes 5/6 x = 10. Then divide both sides by 5/6. Both methods give x = 12.
Challenge
MediumSolve the equation x/2 + x/5 = 14 for x.
Try it yourself
Solve for x
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Fundamentals
4Two-Step Equations
Two Layers to UndoSubtract, Then DivideAdd, Then DivideA Division InsideNegatives in Two StepsRecap: Two-Step Equations7Fractions in Equations
A Fraction CoefficientClearing One DenominatorTwo DenominatorsA Fraction Around a SumCross-MultiplyingRecap: Fractions2One-Step Equations
Undoing MultiplicationUndoing DivisionInverse OperationsRecap: Two Moves in a Row5Tidying First
Like TermsTerms and Numbers MixedThe Distributive PropertyDistributing a SubtractionTidy, Then SolveRecap: Tidying First