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Temperature

Part of the Fundamentals section of Coddy's Algebra journey. Lesson 56 of 61.

The formula F=95C+32F = \frac{9}{5}C+32 converts a Celsius temperature to Fahrenheit. Water boils at 212 °F. To find that temperature in Celsius, substitute F=212F = 212:

212=95C+32212 = \frac{9}{5}C+32

Subtract 32 from both sides to get 180=95C180 = \frac{9}{5}C. Then multiply both sides by 59\frac{5}{9} to undo the fraction coefficient, which gives C=100C = 100. Water boils at 100 °C, so the answer is right.

The equation 212=95C+32212 = \frac{9}{5}C+32 is a two-step equation with a fraction coefficient, and the letter is on the right side. Look at what is done to CC: it is multiplied by 95\frac{9}{5}, and then 32 is added. Undo those two steps in reverse order: subtract 32 first, then multiply by 59\frac{5}{9}.

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Challenge

Medium

A warm day is 68 °F. Substituting into the formula gives 68=95C+3268 = \frac{9}{5}C+32. Solve for CC.

Try it yourself

68=95C+3268 = \frac{9}{5}C+32

Get CC alone

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