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A Perimeter Problem

Part of the Fundamentals section of Coddy's Algebra journey. Lesson 51 of 61.

"A rectangle is 3 cm longer than it is wide, and its perimeter is 26 cm. How wide is it?" Call the width xx. Then the length is x+3x+3. The perimeter is the total of all four sides, which is two lengths plus two widths:

2(x+3)+2x=262\left(x+3\right)+2x = 26

Distribute to get 2x+6+2x=262x+6+2x = 26. Collect the like terms to get 4x+6=264x+6 = 26. Subtract 6 to get 4x=204x = 20, then divide by 4 to get x=5x = 5. The width is 5 cm and the length is 8 cm. Check that 8+5+8+5=268+5+8+5 = 26.

In a geometry problem, a formula gives you the equation. The formula might be for the perimeter, for the area, or for the angles of a triangle adding to 180°. Write the formula with your expressions in it. The result is an ordinary equation, and you solve it in the usual way.

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Challenge

Medium

A rectangle is 4 cm longer than it is wide, and its perimeter is 32 cm, so 2(x+4)+2x=322\left(x+4\right)+2x = 32. Solve for the width xx.

Try it yourself

2(x+4)+2x=322\left(x+4\right)+2x = 32

Get xx alone

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