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Parentheses on One Side

Part of the Fundamentals section of Coddy's Algebra journey. Lesson 29 of 61.

To solve 3(x+2)=2x+103\left(x+2\right) = 2x+10, expand the bracket first, then collect the x-terms.

3x+6=2x+103x+6 = 2x+10

x+6=10x+6 = 10

x=4x = 4

Check: 3(4+2)=183\left(4+2\right) = 18 and 2⋅4+10=182\cdot 4+10 = 18.

Here you must distribute before you collect. While the x is inside the bracket, subtracting 2x2x from both sides gives 3(x+2)−2x3\left(x+2\right)-2x, which is no simpler. So expand the brackets, collect the like terms on each side, then collect across the equals sign. This order solves every linear equation.

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Challenge

Medium

Solve the equation 2(x+5)=x+132\left(x+5\right) = x+13 for xx.

Try it yourself

2(x+5)=x+132\left(x+5\right) = x+13

Get xx alone

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