Sines Past 90°
Part of the Triangles Without Right Angles section of Coddy's Trigonometry journey. Lesson 2 of 44.
A triangle can have an angle over 90°, so the law of sines needs the sine of an obtuse angle. On the unit circle, the sine of an angle is the height of its point. The point at 150° is the mirror image of the point at 30° across the y axis, at the same height.
So sin(150°) = sin(30°), and in general sin(180° - theta) = sin(theta). Every angle strictly between 0° and 180° is above the x axis, so every angle of a triangle has a positive sine.
The catch: a sine does not pin down a triangle's angle. A sine of 1/2 belongs to both 30° and 150°, and both fit in a triangle. When the law of sines hands you an angle, it can hand you two.
Challenge
Tap every angle strictly between 0° and 180° whose sine is √2/2, then press Check.
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Triangles Without Right Angles
2Law of Sines: AAS and ASA
Why the Law of Sines HoldsPair Side With AngleThe Third Angle FirstTwo Coast StationsRecap: Law of Sines8Bearings and Navigation
Reading BearingsTwo Ships From PortTurning Off CourseFinding a Course AngleRecap: Ships at Sea