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Sines Past 90°

Part of the Triangles Without Right Angles section of Coddy's Trigonometry journey. Lesson 2 of 44.

A triangle can have an angle over 90°, so the law of sines needs the sine of an obtuse angle. On the unit circle, the sine of an angle is the height of its point. The point at 150° is the mirror image of the point at 30° across the y axis, at the same height.

The unit circle with the points at 30° and 150° at the same height

So sin(150°) = sin(30°), and in general sin(180° - theta) = sin(theta). Every angle strictly between 0° and 180° is above the x axis, so every angle of a triangle has a positive sine.

The catch: a sine does not pin down a triangle's angle. A sine of 1/2 belongs to both 30° and 150°, and both fit in a triangle. When the law of sines hands you an angle, it can hand you two.

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Challenge

Tap every angle strictly between 0° and 180° whose sine is √2/2, then press Check.

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

quiz iconTest yourself

This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Triangles Without Right Angles