The Height Test
Part of the Triangles Without Right Angles section of Coddy's Trigonometry journey. Lesson 12 of 44.
Before any arcsin you can count the triangles. With A and b fixed, the side a has to reach from C down to the base. The shortest distance from C to the base is the height h = b×sin(A).
For A = 42° and b = 12, h = 12 sin 42°, about 8.03. Then, for an acute A:
a under 8.03: a cannot reach the base, no triangle (the law of sines gives a sine above 1). a equal to h: one right triangle. a between 8.03 and 12: two triangles. a of 12 or more: one triangle, because the second point lands on A or past it.
Challenge
In triangle ABC, A = 40° and AC = 15 cm. Find the height h from C to the base, to two decimal places, then press Check. That height tells you which lengths of BC give two triangles.
Try it yourself
Use the figure to find h
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Triangles Without Right Angles
2Law of Sines: AAS and ASA
Why the Law of Sines HoldsPair Side With AngleThe Third Angle FirstTwo Coast StationsRecap: Law of Sines8Bearings and Navigation
Reading BearingsTwo Ships From PortTurning Off CourseFinding a Course AngleRecap: Ships at Sea3The Ambiguous Case
Finding an AngleTwo TrianglesThe Height TestAn Obtuse Given AngleRadio CoverageRecap: How Many Triangles?