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Area With a Sine

Part of the Triangles Without Right Angles section of Coddy's Trigonometry journey. Lesson 22 of 37.

Area is half the base times the height. Without a right angle the height is not given, but a sine finds it. Take sides a and b with the angle C between them, and lay b along the base. The height is the side opposite C in a right triangle with hypotenuse a, so it is a⋅sin⁡(C)a\cdot \sin\left(C\right).

A=12⋅a⋅b⋅sin⁡(C)A = \frac{1}{2}\cdot a\cdot b\cdot \sin\left(C\right)

Triangle with sides 9 and 4 and 30° between them, area unknown

Sides 4 and 9 with 30° between them: A=12⋅4⋅9⋅sin⁡(30∘)A = \frac{1}{2}\cdot 4\cdot 9\cdot \sin\left(30^{\circ}\right), which is 18 × 1/2 = 9 square units. The angle must be the one between the two sides you multiply. On the board, tap the angle, both sides and the area label, then pick Area with a sine.

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Challenge

Two sides of a triangle are 11 cm and 7 cm, and the angle between them is 38°. Find the area A, to two decimal places, then press Check.

Try it yourself

Use the figure to find A

Use the figure to find A

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Triangles Without Right Angles