添加放映场次
本课属于 Coddy JavaScript 学习旅程的“逻辑与流程”单元。第 62 课,共 65 课。
挑战
简单在 switch 语句中添加一个新的测试用例:addScreening。
对于 addScreening,数据参数包含:
- movieId(数字)
- venueId(数字)
- date(格式为 'YYYY-MM-DD' 的字符串)
- time(格式为 'HH:MM:SS' 的字符串)
该函数应:
- 验证
festivalData中是否存在具有指定movieId的电影,以及具有指定venueId的场馆。如果其中任何一个不存在,就将 "Movie or venue not found!" 添加到结果中 - 检查同一场馆、日期和时间是否没有放映场次。如果场次已存在,就将 "Screening already exists at this time!" 添加到结果中
- 创建一个新的放映场次对象,其中包含:
- id:将放映场次数组的长度加 1 生成
- 从数据中获取 movieId、venueId、date 和 time
- availableSeats:设为场馆的容量
- 将该放映场次添加到
festivalData.screenings数组中 - 将
Screening added successfully!添加到结果数组中
亲手试试
const festivalData = {
movies: [{
id: 1,
title: "Inception",
director: "Christopher Nolan",
year: 2010,
mainGenre: "Sci-Fi",
secondGenre: undefined,
avgRating: 0,
available: true
}],
venues: [{
id: 1,
name: "Main Theater",
capacity: 200,
}],
screenings: [{
id: 1,
movieId: 1,
venueId: 1,
date: '2023-10-29',
time: '13:35:00',
availableSeats: 200
}],
tickets: new Set()
};
function manageFestival(actions, data) {
let results = [];
actions.forEach((action, index) => {
const currentData = data[index];
switch(action) {
case "listMovies":
results.push(festivalData.movies);
break;
case "listVenues":
results.push(festivalData.venues);
break;
case "listTickets":
results.push(festivalData.tickets);
break;
case "listScreenings":
results.push(festivalData.screenings);
break;
case "addMovie":
const newMovie = {
id: festivalData.movies.length + 1,
title: currentData.title,
director: currentData.director,
year: currentData.year,
mainGenre: currentData.mainGenre,
secondGenre: currentData.secondGenre,
avgRating: 0,
available: true
};
festivalData.movies.push(newMovie);
results.push("Movie added successfully!");
break;
case "addVenue":
const newVenue = {
id: festivalData.venues.length + 1,
name: currentData.name,
capacity: currentData.capacity,
};
festivalData.venues.push(newVenue);
results.push("Venue added successfully!");
break;
default:
results.push("Invalid action!");
}
});
return results;
}逻辑与流程中的所有课
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