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本课属于 Coddy GDScript 学习旅程的“逻辑与流程”单元。第 45 课,共 78 课。

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挑战

简单

检查学生是否选修了某门课程。保留你在前面几步中写的所有内容。

1. 函数。在其他函数下方,编写 is_enrolled(student_name: String, course: String) -> bool:

  • 如果 student_records 中没有这个姓名,就打印 Student '<name>' not found. 并返回 false。
  • 否则,如果这门课程在该学生的 "courses" 集合中,就返回 true;如果不在,就返回 false。

2. 命令。在 ["show"] 上方,为 enrolled <name> <course> 添加一个分支,例如 enrolled Alice Math。它会打印 is_enrolled() 返回的值。对于以下命令:

add Alice 20 Math Physics
add Bob 22 Biology Chemistry
enrolled Alice Math
enrolled Alice Biology
enrolled Bob Biology
enrolled Charlie Math
exit

输出为:

Student 'Alice' added successfully.
Student 'Bob' added successfully.
true
false
true
Student 'Charlie' not found.
false
Goodbye!

如果找不到学生,会先显示提示信息,然后显示 false。

亲手试试

extends Node

# 每位学生:姓名 -> {"age": int, "grades": Array, "courses": 课程名称的集合}
var student_records := {}

func _ready():
	while true:
		var parts := Array(OS.read_string_from_stdin().split(" ", false))
		match parts:
			["add", var student, var age, ..]:
				add_student(student, int(age), parts.slice(3))
			["grade", var student, var grade]:
				add_grade(student, int(grade))
			["show"]:
				print(student_records)
			["exit"]:
				print("Goodbye!")
				break

func add_student(student_name: String, age: int, courses: Array) -> void:
	if student_records.has(student_name):
		print("Student '%s' already exists." % student_name)
		return
	var course_set := {}
	for course in courses:
		course_set[course] = true
	student_records[student_name] = {"age": age, "grades": [], "courses": course_set}
	print("Student '%s' added successfully." % student_name)

func add_grade(student_name: String, grade: int) -> void:
	if not student_records.has(student_name):
		print("Student '%s' not found." % student_name)
		return
	student_records[student_name]["grades"].append(grade)
	print("Grade %d added for student '%s'." % [grade, student_name])

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