是否已注册
本课属于 Coddy GDScript 学习旅程的“逻辑与流程”单元。第 45 课,共 78 课。
挑战
简单检查学生是否选修了某门课程。保留你在前面几步中写的所有内容。
1. 函数。在其他函数下方,编写 is_enrolled(student_name: String, course: String) -> bool:
- 如果
student_records中没有这个姓名,就打印Student '<name>' not found.并返回false。 - 否则,如果这门课程在该学生的
"courses"集合中,就返回true;如果不在,就返回false。
2. 命令。在 ["show"] 上方,为 enrolled <name> <course> 添加一个分支,例如 enrolled Alice Math。它会打印 is_enrolled() 返回的值。对于以下命令:
add Alice 20 Math Physics
add Bob 22 Biology Chemistry
enrolled Alice Math
enrolled Alice Biology
enrolled Bob Biology
enrolled Charlie Math
exit输出为:
Student 'Alice' added successfully.
Student 'Bob' added successfully.
true
false
true
Student 'Charlie' not found.
false
Goodbye!如果找不到学生,会先显示提示信息,然后显示 false。
亲手试试
extends Node
# 每位学生:姓名 -> {"age": int, "grades": Array, "courses": 课程名称的集合}
var student_records := {}
func _ready():
while true:
var parts := Array(OS.read_string_from_stdin().split(" ", false))
match parts:
["add", var student, var age, ..]:
add_student(student, int(age), parts.slice(3))
["grade", var student, var grade]:
add_grade(student, int(grade))
["show"]:
print(student_records)
["exit"]:
print("Goodbye!")
break
func add_student(student_name: String, age: int, courses: Array) -> void:
if student_records.has(student_name):
print("Student '%s' already exists." % student_name)
return
var course_set := {}
for course in courses:
course_set[course] = true
student_records[student_name] = {"age": age, "grades": [], "courses": course_set}
print("Student '%s' added successfully." % student_name)
func add_grade(student_name: String, grade: int) -> void:
if not student_records.has(student_name):
print("Student '%s' not found." % student_name)
return
student_records[student_name]["grades"].append(grade)
print("Grade %d added for student '%s'." % [grade, student_name])
逻辑与流程中的所有课
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