优秀学生
本课属于 Coddy Python 学习旅程的“逻辑与流程”单元。第 45 课，共 78 课。
挑战
简单创建一个名为 filter_top_students 的函数，它接受一个参数：threshold（浮点数）。该函数应当：
- 遍历
student_records字典，找出平均成绩高于指定threshold的所有学生。 - 使用
calculate_average_grade函数获取每位学生的平均成绩。 - 返回优秀学生姓名组成的列表。
- 如果没有学生符合条件，则返回一个空列表。
在代码末尾添加（替换为）以下代码块：
add_student("Alice", 20, ["Math", "Physics"])
add_student("Bob", 22, ["Math", "Biology"])
add_student("Diana", 23, ["Chemistry", "Physics"])
add_grade("Alice", 90)
add_grade("Alice", 85)
add_grade("Bob", 75)
add_grade("Diana", 95)
print(filter_top_students(80)) # Should return ["Alice", "Diana"]
print(filter_top_students(90)) # Should return ["Diana"]
print(filter_top_students(100)) # Should return an empty list花点时间回顾一下，你是如何结合字典、集合和决策逻辑来创建一个功能完整的程序的。做得好！🚀
亲手试试
student_records = {}
def add_student(name, age, courses):
if name in student_records:
print(f"Student '{name}' already exists.")
return
student_records[name] = {"age": age, "grades": set(), "courses": set(courses)}
print(f"Student '{name}' added successfully.")
def add_grade(name, grade):
if name not in student_records:
print(f"Student '{name}' not found.")
return
student_records[name]["grades"].add(grade)
print(f"Grade {grade} added for student '{name}'.")
def is_enrolled(name, course):
if name not in student_records:
print(f"Student '{name}' not found.")
return False
return course in student_records[name]["courses"]
def calculate_average_grade(name):
if name not in student_records:
print(f"Student '{name}' not found.")
return None
grades = student_records[name]["grades"]
if not grades:
return 0
return sum(grades) / len(grades)
def list_students_by_course(course):
students_in_course = []
for name, details in student_records.items():
if course in details["courses"]:
students_in_course.append(name)
return students_in_course
add_student("Alice", 20, ["Math", "Physics"])
add_student("Bob", 22, ["Math", "Biology"])
add_student("Diana", 23, ["Chemistry", "Physics"])
print(list_students_by_course("Math")) # Should return ["Alice", "Bob"]
print(list_students_by_course("Physics")) # Should return ["Alice", "Diana"]
print(list_students_by_course("Biology")) # Should return ["Bob"]
print(list_students_by_course("History")) # Should return an empty list逻辑与流程中的所有课
自己练习： Python 在线编译器