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It Always Works

Part of the Factoring & Quadratics section of Coddy's Algebra journey. Lesson 51 of 63.

Here is the formula's real power. x^2 + 3x + 1 = 0: the machine finds no pair, because none exists over whole numbers. The formula does not care: x = (-3 ± √(3^2 - 4 * 1 * 1)) / 2 = (-3 ± √5) / 2.

The discriminant 5 is not a perfect square, so the root stays as the radical √5, exactly as in the square-root chapter. The two solutions are exact irrational numbers, and the formula wrote them down without complaint.

That is the division of labor: factoring is fast when it works, the formula works always. When the discriminant is a perfect square you could have factored; when it is not, the formula was the only road, and the radical in the answer is the proof.

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Challenge

Hard

Solve x^2 + 5x + 2 = 0 exactly. The radical will survive to the answer, and that is correct. Factoring chips are off.

Try it yourself

x^2 + 5x + 2 = 0

Solve for x

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