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The Double Root

Part of the Factoring & Quadratics section of Coddy's Algebra journey. Lesson 53 of 61.

When the discriminant is zero, the equation has one solution. Take x2−4x+4=0x^{2}-4x+4 = 0. The left side is a perfect square trinomial, so you can write it as (x−2)2=0\left(x-2\right)^{2} = 0. A square is zero only when the number being squared is zero, so x−2=0x-2 = 0 and x=2x = 2. There is one solution.

You can also factor the left side as (x−2)(x−2)=0\left(x-2\right)\left(x-2\right) = 0. Both factors give the same equation, x−2=0x-2 = 0, so both give the same solution. A solution that comes from two equal factors is called a double root. The double root of this equation is 2.

The discriminant of x2−4x+4=0x^{2}-4x+4 = 0 is also zero. Here b2b^{2} is 16 and 4ac4ac is 16, so the discriminant is 16−16=016-16 = 0. Because it is zero, the plus and the minus in the quadratic formula give the same value, x=2x = 2. The formula, the factoring and the squared form all agree that the equation has one solution.

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Challenge

Medium

Solve x2−14x+49=0x^{2}-14x+49 = 0. Before you start, decide how many solutions you expect.

Try it yourself

x2−14x+49=0x^{2}-14x+49 = 0

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