Final: The Rug, Solved
Part of the Factoring & Quadratics section of Coddy's Algebra journey. Lesson 62 of 63.
To solve an equation from a word problem, first expand any product. Then move every term to one side so that the other side is zero, factor, and set each factor equal to zero. Finally, check each solution against the story. A width or a length must be positive, so a negative solution is rejected.
For example, a rectangle with width x, length x + 2 and area 15 gives x(x + 2) = 15. Expanding gives x^2 + 2x = 15, and subtracting 15 from both sides gives x^2 + 2x - 15 = 0. This factors as (x + 5)(x - 3) = 0, so x = -5 or x = 3. A width cannot be -5, so the width is 3 and the length is 5. Both values solve the equation, but only one of them fits the rectangle.
Challenge
HardSolve x(x + 3) = 40 for x. Give both solutions, then decide which one can be the width of the rug.
Try it yourself
Solve for x
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Factoring & Quadratics
1What Factoring Is
Two DirectionsThe Reverse GearUn-Distributing LettersThe Check Is MultiplicationRecap: First Factors4Minus Signs in the Machine
A Negative ProductWhich One Gets the MinusBoth NegativeThe Sign MapRecap: Signs2The Greatest Common Factor
Number and Letter TogetherThe Largest OneHigher PowersThree Terms Share TooRecap: The GCF5Special Shapes
A Missing MiddleThe Shape in LettersThe Perfect SquareThe Minus VersionPrime PolynomialsRecap: Special Shapes3The Sum-Product Machine
Reading the ProductHunting the PairThe Machine in LettersLonger HuntsRecap: The Machine6Factor Completely
Two LayersSquares InsideCompletely Means CompletelyThe Deep CheckRecap: Factor Completely9The Square Root Method
Undoing a SquareArrange, Then RootA Squared PackageRoots That Are Not WholeRecap: Square Roots12Final Challenges
Final: The Full SweepFinal: Factor and SplitFinal: Arrange FirstFinal: The Rug, ModeledFinal: The Rug, SolvedFinal: No Training Wheels