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The Bare X

Part of the Factoring & Quadratics section of Coddy's Algebra journey. Lesson 32 of 61.

In x(x+2)=0x\left(x+2\right) = 0, the factors are xx and x+2x+2. Set each factor equal to zero: x=0x = 0 or x+2=0x+2 = 0. The solutions are 0 and -2.

Substitute x=0x = 0 into the original equation. You get 0(0+2)=00\left(0+2\right) = 0, so 0 is a solution. Include this case as well as x=−2x = -2.

The single letter xx in front of the parentheses is a factor too. Include it when you split the equation. It gives the solution x=0x = 0. The other factor gives the second solution. Check each answer by substituting it into the original equation.

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Challenge

Easy

Solve x(x−9)=0x\left(x-9\right) = 0. Count the factors first.

Try it yourself

x(x−9)=0x\left(x-9\right) = 0

Get xx alone

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