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Higher Powers

Part of the Factoring & Quadratics section of Coddy's Algebra journey. Lesson 7 of 61.

x5+x3=x3(x2+1){x}^{5}+{x}^{3} = {x}^{3}\left({x}^{2}+1\right)

Only three xx's go in front, because x3{x}^{3} has only three. Take out the smallest power. The 1 stays, because x3x3\frac{{x}^{3}}{{x}^{3}} is 1. With three terms, the factor must divide all three.

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Challenge

Factor 2x4+6x3+2x22{x}^{4}+6{x}^{3}+2{x}^{2} completely.

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2x4+6x3+2x22x^{4}+6x^{3}+2x^{2}

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