One Factor Is Enough
Part of the Factoring & Quadratics section of Coddy's Algebra journey. Lesson 33 of 63.
A product is zero if at least one of its factors is zero. In (x - 4)(x + 6) = 0, substitute x = 4. The first factor is 0 and the second factor is 10, so the product is 0 × 10 = 0. The second factor does not need to be zero as well.
Each case is solved on its own. In the first case, the first factor is zero, which gives x = 4. In the second case, the second factor is zero, which gives x = -6. Each of the answers, 4 and -6, makes the original equation true by itself. You can check this by substituting each one.
Solve each factor equation separately, and join the solutions with the word or. For (x - 4)(x + 6) = 0, the solutions are x = 4 or x = -6. A solution needs to make at least one factor zero. It does not need to make both factors zero.
Challenge
EasySolve (x - 1)(x + 8) = 0.
Try it yourself
Solve for x
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Factoring & Quadratics
1What Factoring Is
Two DirectionsThe Reverse GearUn-Distributing LettersThe Check Is MultiplicationRecap: First Factors4Minus Signs in the Machine
A Negative ProductWhich One Gets the MinusBoth NegativeThe Sign MapRecap: Signs7The Zero Product Rule
A Product That Makes ZeroOne Factor Is EnoughThe Bare XEvery Factor Gets a TurnRecap: Zero Product2The Greatest Common Factor
Number and Letter TogetherThe Largest OneHigher PowersThree Terms Share TooRecap: The GCF5Special Shapes
A Missing MiddleThe Shape in LettersThe Perfect SquareThe Minus VersionPrime PolynomialsRecap: Special Shapes3The Sum-Product Machine
Reading the ProductHunting the PairThe Machine in LettersLonger HuntsRecap: The Machine6Factor Completely
Two LayersSquares InsideCompletely Means CompletelyThe Deep CheckRecap: Factor Completely