Menu

Binomial Times Binomial

Part of the Exponents & Polynomials section of Coddy's Algebra journey. Lesson 47 of 62.

To multiply two binomials, such as (x+2)(x+3)\left(x+2\right)\left(x+3\right), treat the first binomial as a single multiplier and distribute it over the second: (x+2)x+(x+2)⋅3\left(x+2\right)x+\left(x+2\right)\cdot 3. Then distribute each of those products in turn. Now every term of the first binomial has been multiplied by every term of the second: x2+3x+2x+6x^{2}+3x+2x+6.

Collect the middle terms to get x2+5x+6x^{2}+5x+6. There are four products in all: the first terms, the outer terms, the inner terms and the last terms. Each pair of terms is multiplied once.

The two middle terms, 3x3x and 2x2x, are the cross products. They add to 5x5x. Their coefficient, 5, is the sum of 2 and 3, and the constant 6 is the product of 2 and 3. You will use this relationship to factor trinomials in the next section.

challenge icon

Challenge

Medium

Expand (x+4)(x+2)\left(x+4\right)\left(x+2\right) and collect the middle terms.

Try it yourself

(x+4)(x+2)\left(x+4\right)\left(x+2\right)

Simplify

All lessons in Exponents & Polynomials