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Binomial Times Binomial

Part of the Exponents & Polynomials section of Coddy's Algebra journey. Lesson 49 of 64.

(x+2)(x+3) multiplies two packages. Treat the first as a single multiplier and distribute it, exactly as if it were a monomial: (x+2) * x + (x+2) * 3. Distribute each of those in turn, and every term of the first package has met every term of the second: x^2 + 3x + 2x + 6.

Collect the middle: x^2 + 5x + 6. Four little products, one collection. The pattern is worth naming: firsts, outers, inners, lasts; every pairing exactly once.

The middle terms are the news here. The x-terms 3x and 2x came from cross products, and their sum, 5, is the sum of the 2 and 3 you started with, while the constant 6 is their product. That observation becomes a factoring machine in the next section.

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Challenge

Medium

Expand (x+4)(x+2) and collect the middle terms.

Try it yourself

(x+4)(x+2)

Simplify the expression

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