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Dividing by a Variable Term

Part of the Exponents & Polynomials section of Coddy's Algebra journey. Lesson 55 of 64.

When the divisor contains x, split the fraction in the same way. Then use the quotient rule on each piece: divide the coefficients and subtract the exponents. For (6x^2 + 9x)/(3x), the pieces are 6x^2/(3x) = 2x and 9x/(3x) = 3.

The quotient is 2x + 3. Look at the second term. In 9x/(3x), the x on top and the x below cancel, because x/x = 1. Only the number 3 is left. A term loses its x completely when the divisor has the same power of x.

There is a second method. Factor the numerator as 3x(2x + 3), then cancel the common factor 3x from the top and the bottom, for nonzero x. Both methods give 2x + 3. The next section explains how to factor polynomial expressions.

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Challenge

Medium

Divide: (12x^2 + 8x)/(4x).

Try it yourself

(12x^2 + 8x)/(4x)

Simplify the expression

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