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Dividing by a Variable Term

Part of the Exponents & Polynomials section of Coddy's Algebra journey. Lesson 55 of 64.

Now the divisor carries an x: (6x^2 + 9x)/(3x). Split as before, and each piece is a full quotient-rule job: coefficients divide, exponents subtract. 6x^2/(3x) = 2x and 9x/(3x) = 3.

The quotient is 2x + 3. Note what happened to the second term: 9x/(3x) lost its x entirely, x/x = 1, leaving a plain 3. Terms can and do drop out of the letter business when the division exactly consumes their x.

Another road to the same place: factor the top first, 3x(2x + 3), and cancel the 3x whole. Splitting and factoring are both legal; the factoring road is about to become the main highway of the next section.

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Challenge

Medium

Divide: (12x^2 + 8x)/(4x).

Try it yourself

(12x^2 + 8x)/(4x)

Simplify the expression

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