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Splitting the Fraction

Part of the Exponents & Polynomials section of Coddy's Algebra journey. Lesson 54 of 64.

To divide a sum by a number, divide each term by that number. So (6x^2 + 9x)/3 splits into 6x^2/3 + 9x/3. Now you have two small divisions instead of one large one.

In each piece, divide the coefficient: 6/3 = 2 and 9/3 = 3. The quotient is 2x^2 + 3x. The powers of x do not change, because the divisor 3 has no x to cancel.

To check a division, multiply the quotient by the divisor. You should get the original sum back: 3(2x^2 + 3x) = 6x^2 + 9x. Dividing a sum term by term is the distributive law used in reverse.

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Challenge

Medium

Divide: (10x^2 + 8x)/2.

Try it yourself

(10x^2 + 8x)/2

Simplify the expression

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