容器魔术方法
本课属于 Coddy Python 学习旅程的“面向对象编程”单元。第 35 课,共 64 课。
容器魔术方法可以让你的类像内置容器(列表、字典等)一样运行。它们让自定义对象支持索引、检查长度和迭代。
下面是一个包含容器魔术方法的类示例:
class CustomList:
def __init__(self, items):
self.items = items
def __len__(self):
return len(self.items)
def __getitem__(self, index):
return self.items[index]
def __setitem__(self, index, value):
self.items[index] = value
def __iter__(self):
return iter(self.items)
def __contains__(self, item):
return item in self.items__len__ 方法让 len() 可以正常使用:
my_list = CustomList([1, 2, 3, 4])
print(len(my_list)) # 4__getitem__ 方法支持通过索引获取元素:
print(my_list[2]) # 3
print(my_list[0]) # 1__setitem__ 方法支持通过索引赋值:
my_list[1] = 10
print(my_list[1]) # 10__contains__ 方法让 in 运算符生效:
print(3 in my_list) # True
print(100 in my_list) # False__iter__ 方法支持迭代:
for item in my_list:
print(item)输出:
4
3
1
10
True
False
1
10
3
4要点:像 __len__、__getitem__、__setitem__、__iter__ 和 __contains__ 这样的容器魔术方法,可以让你自定义的类表现得像内置容器一样。这样,你的对象就能支持直观的索引、迭代和成员测试。
挑战
中等在这个挑战中,你将实现一个 Deck 类,用于模拟一副扑克牌,并实现全面的功能,同时遵循 Python 的惯例。
你只需要编辑 deck.py 文件。按照代码中的 TODO 注释,逐步实现以下内容:
- 初始化一副标准的 52 张牌(使用类似 "2H"、"KD"、"AS" 的字符串)
- 支持 Python 内置操作:
- 索引访问(
deck[0]) - 长度检查(
len(deck)) - 迭代(
for card in deck) - 成员测试(
"AS" in deck)
- 索引访问(
- 实现
shuffle方法,随机打乱牌的顺序
亲手试试
from deck import Deck
# 综合测试用例处理
test_case = input()
def test_basic_functionality():
deck = Deck()
assert len(deck) == 52, f"Deck should have 52 cards, but has {len(deck)}"
first_card = deck[0]
assert isinstance(first_card, str), f"Card should be a string, but got {type(first_card)}"
assert "AS" in deck, "Ace of Spades should be in the deck"
assert "XY" not in deck, "XY is not a valid card and should not be in the deck"
cards = [card for card in deck]
assert len(cards) == 52, f"Iteration should yield 52 cards, but got {len(cards)}"
original_first_five = [deck[i] for i in range(5)]
deck.shuffle()
shuffled_first_five = [deck[i] for i in range(5)]
assert original_first_five != shuffled_first_five or len(deck) <= 5, "Shuffle should change card order"
print("Basic functionality tests passed!")
def test_edge_cases():
deck = Deck()
# 测试能否访问第一张和最后一张牌
first_card = deck[0]
last_card = deck[51]
assert isinstance(first_card, str) and isinstance(last_card, str), "First and last cards should be strings"
# 测试负数索引
assert deck[-1] == deck[51], "Negative indexing should work correctly"
# 测试访问超出范围的位置
try:
invalid_card = deck[52]
print("Test failed: Should raise IndexError for out of bounds access")
except IndexError:
print("Edge case test passed: IndexError raised for out of bounds access")
print("Edge case tests passed!")
def test_card_uniqueness():
deck = Deck()
cards = [card for card in deck]
unique_cards = set(cards)
assert len(unique_cards) == 52, f"All cards should be unique, but found {len(unique_cards)} unique cards"
# 确认指定的牌存在
expected_cards = ["2H", "10S", "KD", "AC"]
for card in expected_cards:
assert card in deck, f"Expected card {card} not found in deck"
print("Card uniqueness tests passed!")
def test_shuffle_behavior():
deck = Deck()
original_order = [card for card in deck]
# 第一次洗牌
deck.shuffle()
first_shuffle = [card for card in deck]
assert len(first_shuffle) == 52, "Shuffle should preserve all 52 cards"
assert set(first_shuffle) == set(original_order), "Shuffle should not add or remove cards"
# 顺序很可能已经改变(但也有极小的概率没变)
different_order = (original_order != first_shuffle)
# 再洗一次牌,确保顺序改变
deck.shuffle()
second_shuffle = [card for card in deck]
different_order_2 = (first_shuffle != second_shuffle)
assert different_order or different_order_2, "Multiple shuffles should change the order"
print("Shuffle behavior tests passed!")
def test_contains_behavior():
deck = Deck()
# 测试所有有效的牌是否都在牌组中
suits = ['H', 'D', 'C', 'S']
ranks = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']
for suit in suits:
for rank in ranks:
card = rank + suit
assert card in deck, f"Valid card {card} should be in the deck"
# 测试无效的牌是否都不在牌组中
invalid_cards = ["1H", "11S", "XD", "AX", "JX", ""]
for card in invalid_cards:
assert card not in deck, f"Invalid card {card} should not be in the deck"
print("Contains behavior tests passed!")
def test_iteration_behavior():
deck = Deck()
# 测试迭代
card_count = 0
for card in deck:
card_count += 1
assert isinstance(card, str), f"Each card should be a string, but got {type(card)}"
assert card_count == 52, f"Iteration should yield 52 cards, but got {card_count}"
# 测试多次迭代
first_iteration = [card for card in deck]
second_iteration = [card for card in deck]
assert first_iteration == second_iteration, "Multiple iterations should yield the same order"
print("Iteration behavior tests passed!")
# 根据输入运行相应的测试
if test_case == "basic_functionality":
test_basic_functionality()
elif test_case == "edge_cases":
test_edge_cases()
elif test_case == "card_uniqueness":
test_card_uniqueness()
elif test_case == "shuffle_behavior":
test_shuffle_behavior()
elif test_case == "contains_behavior":
test_contains_behavior()
elif test_case == "iteration_behavior":
test_iteration_behavior()
else:
# 默认测试:运行原有的测试套件
def test_deck():
try:
# 测试初始化和长度
deck = Deck()
assert len(deck) == 52, f"Deck should have 52 cards, but has {len(deck)}"
# 测试 getitem
first_card = deck[0]
assert isinstance(first_card, str), f"Card should be a string, but got {type(first_card)}"
# 测试 contains
assert "AS" in deck, "Ace of Spades should be in the deck"
assert "XY" not in deck, "XY is not a valid card and should not be in the deck"
# 测试迭代
cards = [card for card in deck]
assert len(cards) == 52, f"Iteration should yield 52 cards, but got {len(cards)}"
assert len(set(cards)) == 52, "All cards in the deck should be unique"
# 测试 shuffle(基本检查:顺序是否发生变化)
original_first_five = [deck[i] for i in range(5)]
deck.shuffle()
shuffled_first_five = [deck[i] for i in range(5)]
assert original_first_five != shuffled_first_five or len(deck) <= 5, "Shuffle should change card order"
# 检查 shuffle 是否会丢失卡牌
assert len(deck) == 52, f"Deck should still have 52 cards after shuffle, but has {len(deck)}"
print("All tests passed!")
except AssertionError as e:
print(f"Test failed: {e}")
test_deck()
print("Tests completed")这节课包含一个小测验。开始学习即可作答,并记录你的进度。
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