Practice #4
Lesson 13 of 14 in Coddy's Linked List - Data Structures Series #5 course.
Challenge
EasyGiven two sorted integer arrays a and b (the values of two sorted linked lists), write a function mergeSorted that returns a single sorted array containing all values from both inputs.
Use a linked list to solve this problem! Walk both lists in parallel, repeatedly taking the smaller head into your result.
You must use the LinkedList class (provided in linkedlist.<ext> along with node.<ext>) — do not use language built-ins like arrays' built-in reverse, slicing, or stdlib list operations to compute the result.
Try it yourself
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "solution.h"
int main() {
char line1[8192];
char line2[8192];
if (!fgets(line1, sizeof(line1), stdin)) line1[0] = '\0';
if (!fgets(line2, sizeof(line2), stdin)) line2[0] = '\0';
int a[4096];
int alen = 0;
char* tok = strtok(line1, " \t\r\n");
while (tok) { a[alen++] = atoi(tok); tok = strtok(NULL, " \t\r\n"); }
int b[4096];
int blen = 0;
tok = strtok(line2, " \t\r\n");
while (tok) { b[blen++] = atoi(tok); tok = strtok(NULL, " \t\r\n"); }
int rs = 0;
int* r = mergeSorted(a, alen, b, blen, &rs);
for (int idx = 0; idx < rs; idx++) {
if (idx > 0) printf(" ");
printf("%d", r[idx]);
}
printf("\n");
return 0;
}
