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A Point and a Slope

Part of the Graphs & Systems section of Coddy's Algebra journey. Lesson 23 of 64.

A slope and one point, any point, also pin a line down, and there is a form built for exactly that data. A line through (x1, y1) with slope m satisfies

y - y1 = m(x - x1)

the point-slope form. Through (1, 2) with slope 3 it reads y - 2 = 3(x - 1), and expanding turns it into slope-intercept: y - 2 = 3x - 3, so y = 3x - 1.

The form is just the slope formula rearranged: any (x, y) on the line makes rise over run equal m, and multiplying by the run gives the equation. Plug in the known point, expand, done.

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Challenge

A line through (1, 2) with slope 3 satisfies y - 2 = 3(x - 1). Rewrite it in slope-intercept form: solve for y and multiply everything out.

Try it yourself

y - 2 = 3(x - 1)

Solve for y

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Graphs & Systems