Substitution
Part of the Graphs & Systems section of Coddy's Algebra journey. Lesson 52 of 64.
When one equation already says what a variable equals, push that expression into the other equation. In y = 2x - 1; x + y = 5 the first line hands over y, so the second becomes one equation in one variable:
x + (2x - 1) = 5
3x - 1 = 5
x = 2
Then y comes from the line that named it: y = 2(2) - 1 = 3. The solution is the pair x = 2, y = 3, the crossing computed instead of read off a picture.
Substitution shines exactly when a variable stands alone somewhere; the whole first move costs nothing because the isolating is already done.
Challenge
Solve the system y = x + 1; 2x + y = 7 for x and y.
Try it yourself
Solve for x,y
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Graphs & Systems
1The Coordinate Plane
Two Numbers, One PointThe Four QuadrantsPoints on the AxesMirror PointsRecap: The Plane4Slope-Intercept Form
y = mx + bThe Starting HeightWrite the EquationSolve for yDraw From Any FormRecap: y = mx + b7Parallel & Perpendicular
Same Slope, Never MeetThe Perpendicular SlopeA Right-Angle LineRecap: Two Relations2From Rule to Line
A Rule Makes PointsThe Points Line UpOn the Line or Not?Between the DotsRecap: Rule to Line5Point-Slope Form
A Point and a SlopeFrom Two PointsFlat or Vertical ThroughDraw From a PointRecap: Point-Slope11Solving Systems Exactly
SubstitutionIsolate FirstEliminationScale, Then AddThree UnknownsTwo Numbers, Two FactsRecap: Two Methods