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A Right-Angle Line

Part of the Graphs & Systems section of Coddy's Algebra journey. Lesson 32 of 61.

To draw a perpendicular line through a given point, first find the perpendicular slope. Then draw the line through the point with that slope, the same way you draw any line from a point and a slope. The slope of y=12x+1y = \frac{1}{2}x+1 is 12\frac{1}{2}, so the perpendicular slope is -2. The perpendicular line through (0, -1) is y=−2x−1y = -2x-1.

The two lines cross once, at a right angle. The first line rises 12\frac{1}{2} for each step to the right. The second line falls 2 for each step to the right. The product of the two slopes is 12⋅(−2)=−1\frac{1}{2}\cdot \left(-2\right) = -1.

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Challenge

Medium

The line y=12x−1y = \frac{1}{2}x-1 is drawn. Draw the line perpendicular to it through (0, 3).

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Draw the line

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