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Combine All Products

Parte de la sección Fundamentos del Journey de SQL de Coddy. Lección 55 de 72.

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Desafío

Intermedio

Tablas y columnas disponibles:

  • <strong>enom_gilpane</strong>: <strong>part_id</strong>, <strong>rpm</strong>, <strong>watt</strong>, <strong>size</strong>
  • <strong>castle_loctus</strong>: <strong>part_id</strong>, <strong>rpm</strong>, <strong>watt</strong>, <strong>size</strong>
  • <strong>honpan_bilopsa</strong>: <strong>part_id</strong>, <strong>rpm</strong>, <strong>watt</strong>, <strong>size</strong>
  • <strong>yurnol_qoltam</strong>: <strong>part_id</strong>, <strong>rpm</strong>, <strong>watt</strong>, <strong>size</strong>

Ahora calcula la misma calidad para todos los productos (Cada tabla es un producto) y combínalos todos usando UNION ALL:

quality_table as (
    SELECT * FROM filtered_quality_1
    UNION ALL
    SELECT * FROM filtered_quality_2
    UNION ALL 
    SELECT * FROM filtered_quality_3
    UNION ALL 
    SELECT * FROM filtered_quality_4
)

Devuelve part_id y quality

Pruébalo tú mismo

-- El primer bloque de producto está hecho para ti, transferido de la lección anterior
WITH filtered_enom_gilpane_quality as (
    WITH enom_gilpane_quality as (
        SELECT part_id, ((rpm * watt) / size) as quality
        FROM (
            SELECT part_id, rpm, watt + (select avg(watt) from enom_gilpane) as watt, size
            FROM enom_gilpane
        )
    )

    SELECT *
    FROM enom_gilpane_quality
    WHERE quality > (select avg(quality) from enom_gilpane_quality)
),
-- Construye el mismo bloque para cada una de las tres tablas de productos a continuación
filtered_castle_loctus_quality as (
    ____
),
filtered_honpan_bilopsa_quality as (
    ____
),
filtered_yurnol_qoltam_quality as (
    ____
),
-- Apila los cuatro bloques uno encima del otro, manteniendo cada fila
quality_table as (
    SELECT * FROM filtered_enom_gilpane_quality
    ____
)

SELECT ____
FROM quality_table

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