12 V across a 4 Ω resistor
V = 12 V, R = 4 ΩThe current comes from Ohm's law: I = V/R = 12 / 4 = 3 A. With the current known, the power is P = VI = 12 · 3 = 36 W. P = I²R gives the same: 3² · 4 = 36 W.
Any two of voltage, current, resistance and power give the other two.
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The Coddy physics course teaches the method: you solve each problem in steps on an interactive board, and it tells you which step went wrong.
Ohm's law links the three numbers of a simple circuit: the voltage V across a component, in volts, the current I through it, in amperes, and its resistance R, in ohms. The formula is V = IR, so I = V/R and R = V/I. One ohm is one volt per ampere: a 4 Ω resistor with 12 V across it carries 12 / 4 = 3 A.
Power is the rate the component turns electrical energy into heat or light, in watts, and P = VI. Put V = IR into it and you get two more forms, P = I²R and P = V²/R. Between them, these four formulas mean that any two of V, I, R and P are enough to find the other two, which is what the Ohm's law wheel on a classroom wall shows.
The calculator does exactly that. Fill in any two of the four boxes and leave the other two blank: it finds one blank with whichever formula fits, then uses that answer to find the last one, and shows which formula each step used. Millivolts, milliamps, kilohms and kilowatts are converted to volts, amps, ohms and watts first, as their own step, and each answer is also given in the other units.
Any two of voltage, current, resistance and power. A kettle label gives power and voltage; a resistor's colour bands give its resistance.
Milliamps divide by 1000, kilohms multiply by 1000, kilowatts multiply by 1000. 20 mA is 0.02 A and 2 kW is 2000 W.
V = IR for voltage, current and resistance; P = VI, P = I²R or P = V²/R when power is involved. Rearrange it for the unknown.
Once you have three of the four, any formula that holds the last one gives it. From V and I, for example, P = VI.
Every quantity from every pair of the others. V in volts, I in amperes, R in ohms, P in watts.
| To find | You know | Formula |
|---|---|---|
| Voltage V | I and R | V = IR |
| Voltage V | P and I | V = P/I |
| Voltage V | P and R | V = √(PR) |
| Current I | V and R | I = V/R |
| Current I | P and V | I = P/V |
| Current I | P and R | I = √(P/R) |
| Resistance R | V and I | R = V/I |
| Resistance R | V and P | R = V²/P |
| Resistance R | P and I | R = P/I² |
| Power P | V and I | P = VI |
| Power P | I and R | P = I²R |
| Power P | V and R | P = V²/R |
V = 12 V, R = 4 ΩThe current comes from Ohm's law: I = V/R = 12 / 4 = 3 A. With the current known, the power is P = VI = 12 · 3 = 36 W. P = I²R gives the same: 3² · 4 = 36 W.
V = 230 V, P = 2 kW2 kW is 2000 W. The current is I = P/V = 2000 / 230 = 8.70 A, and then the resistance is R = V/I = 230 / 8.696 = 26.45 Ω. P = V²/R checks it: 230² / 26.45 = 2000 W. That current is why a kettle needs a thicker cable than a lamp.
I = 20 mA, R = 220 ΩConvert first: 20 mA = 0.02 A. Then V = IR = 0.02 · 220 = 4.4 V across the resistor, and P = VI = 4.4 · 0.02 = 0.088 W, which is 88 mW. A common quarter watt resistor (250 mW) handles that easily.
V = 230 V, P = 60 WI = P/V = 60 / 230 = 0.261 A, and R = V/I = 230 / 0.26087 = 881.7 Ω. That is the filament's resistance while it glows. Measured cold with a meter it reads much lower, because a filament lamp is not ohmic: its resistance rises as it heats up.
Ohm's law says the current through a conductor is proportional to the voltage across it, as long as its temperature stays the same. As a formula, V = IR, where V is in volts, I in amperes and R in ohms. It is named after Georg Ohm, who published it in 1827.
Rearrange V = IR. The current is I = V/R and the resistance is R = V/I. A 9 V battery across a 3 kΩ resistor drives 9 / 3000 = 0.003 A, which is 3 mA.
P = VI, in watts when V is in volts and I in amperes. If you know the resistance instead of one of them, use P = I²R or P = V²/R. All three give the same answer for the same component.
A circle split into four quarters, one each for V, I, R and P, holding the twelve formulas that give each quantity from two of the others. The table on this page lists the same twelve formulas.
A conductor whose resistance stays constant, so a graph of current against voltage is a straight line through zero. A metal resistor at a steady temperature is ohmic. A filament lamp is not, because its resistance rises as it heats, and neither is a diode, which barely conducts one way.
For a plain resistor, yes, with the RMS values of the voltage and current. The 230 V or 120 V of mains electricity is already an RMS value, which is why the kettle example works. Coils and capacitors need impedance instead, which this calculator does not cover.
The ohm, Ω. One ohm is one volt per ampere: a resistance of 1 Ω lets 1 A flow when 1 V is across it. Resistors are often marked in kilohms (1 kΩ = 1000 Ω) or megohms (1 MΩ = 1,000,000 Ω).