Math Problem of the Day
One problem a day. A new one at midnight UTC.
Last updated
Today · Completing the Square
- Write in vertex form.−3x² + 6x − 7Answer−3×(x−1)²−4
Take −3 out of the x terms
−3×(x²−2×x)−7Complete the square
−3×((x−1)²−1)−7Expand
−3×(x−1)²+3−7Work out −3×(x−1)²+3−7
−3×(x−1)²−4
Earlier days
- Write in vertex form.−3x² + 6x − 8Answer−3×(x−1)²−5
Take −3 out of the x terms
−3×(x²−2×x)−8Complete the square
−3×((x−1)²−1)−8Expand
−3×(x−1)²+3−8Work out −3×(x−1)²+3−8
−3×(x−1)²−5
- Solve for y.5x + 3y = 6Answery=2−5/3×x
Move 5×x to the other side
3×y=6−5×xMove 3 to the other side
y=(6−5×x)/3Split the fraction
y=2−5/3×x
- Write in vertex form.−3x² + 6x − 6Answer−3×(x−1)²−3
Take −3 out of the x terms
−3×(x²−2×x)−6Complete the square
−3×((x−1)²−1)−6Expand
−3×(x−1)²+3−6Work out −3×(x−1)²+3−6
−3×(x−1)²−3
- Solve for x.1 <= 2x + 9 < 17Answer−4<=x; x<4
Subtract 9 from all parts
−8<=2×x; 2×x<8Divide all parts by 2
−4<=x; x<4
- Solve for x.x² − 225 = 0Answerx=15, x=−15
Move −225 to the other side
x²=225Take the square root of both sides
x=15, x=−15
The problem comes from one of the practice topics, from the order of operations to radicals. The six days before today stay below with their answers.
Common questions
- When does the problem change?
- Every day at midnight UTC.
- Where is the answer?
- Under the problem, hidden until you open it.
