0 to 100 km/h
v₀ = 0 km/h, v = 100 km/h, t = 6.2 sConvert first: 100 km/h = 100 · 1000/3600 = 27.78 m/s. Then a = (27.78 − 0)/6.2 = 4.48 m/s², a little under half the acceleration of free fall.
Acceleration from a change in velocity, or from a force and a mass.
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The Coddy physics course teaches the method: you solve each problem in steps on an interactive board, and it tells you which step went wrong.
Acceleration is how quickly a velocity changes. The average acceleration over a time is a = (v − v₀)/t: the final velocity minus the initial velocity, divided by the time the change took. With velocities in m/s and the time in seconds, the answer is in metres per second squared, m/s².
The sign matters. Take the direction of motion as positive, and a negative acceleration means slowing down: a car braking from 25 m/s to a stop in 5 s has a = (0 − 25)/5 = −5 m/s², a deceleration of 5 m/s². If you know the force instead of the velocities, Newton's second law gives a = F/m: a net force of 500 N on a 1200 kg car gives 0.417 m/s².
The calculator has a tab for each way. In the first, fill in any three of acceleration, initial velocity, final velocity and time and it finds the fourth; in the second, any two of acceleration, force and mass. Speeds in km/h, mph or ft/s and masses in grams or pounds are converted to SI units first, and every step of the working is shown.
Final minus initial: v − v₀. From 0 to 100 km/h the change is 100 km/h.
km/h divide by 3.6, mph multiply by 0.44704. 100 km/h is 27.78 m/s. The calculator does this and shows the factor.
a = 27.78 / 6.2 = 4.48 m/s².
Positive along the direction you chose, negative against it. Braking while moving forward gives a negative answer.
Rounded values from a = (v − v₀)/t for typical figures. A negative value is slowing down.
| Situation | Velocity change | Time | Acceleration |
|---|---|---|---|
| Bus pulling away | 0 to 50 km/h | 15 s | 0.93 m/s² |
| Family car | 0 to 100 km/h | 10 s | 2.78 m/s² |
| Sprinter's start | 0 to 10 m/s | 2 s | 5 m/s² |
| Sports car | 0 to 100 km/h | 3 s | 9.26 m/s² |
| Dropped stone | 0 to 29.43 m/s | 3 s | 9.81 m/s² |
| Car braking hard | 100 km/h to 0 | 4 s | −6.94 m/s² |
v₀ = 0 km/h, v = 100 km/h, t = 6.2 sConvert first: 100 km/h = 100 · 1000/3600 = 27.78 m/s. Then a = (27.78 − 0)/6.2 = 4.48 m/s², a little under half the acceleration of free fall.
v₀ = 25 m/s, v = 0 m/s, t = 5 sa = (0 − 25)/5 = −5 m/s². The minus sign says the acceleration points against the motion: the car loses 5 m/s of speed every second.
F = 500 N, m = 1200 kgIn the force and mass tab, a = F/m = 500 / 1200 = 0.417 m/s². Halve the mass and the same force gives twice the acceleration.
v₀ = 10 m/s, v = 20 m/s, a = 2 m/s²Leave the time blank: t = (v − v₀)/a = (20 − 10)/2 = 5 s.
a = (v − v₀)/t: final velocity minus initial velocity, divided by the time. With velocities in m/s and time in seconds, the answer is in m/s². From rest to 27.78 m/s in 6.2 s is 4.48 m/s².
Rearrange Newton's second law, F = ma, to a = F/m. A net force of 500 N on a 1200 kg car gives 500 / 1200 = 0.417 m/s². The force must be in newtons and the mass in kilograms.
Acceleration that slows an object down. With the direction of motion as positive it comes out negative: from 25 m/s to rest in 5 s is −5 m/s², a deceleration of 5 m/s².
Metres per second squared, m/s². It means the velocity changes by that many m/s each second. Accelerations are also given in ft/s² (1 ft/s² = 0.3048 m/s²) or as multiples of g, 9.81 m/s².
From rest with constant acceleration, s = ½at² rearranges to a = 2s/t², so 100 m in 10 s gives 2 · 100 / 10² = 2 m/s². With a starting velocity, use s = ut + ½at²; the kinematics calculator solves it.
Yes. It has a size and a direction, the direction of the change in velocity. That is why the sign of the answer matters, and why a car turning a corner at a steady speed is still accelerating.
At about 9.81 m/s² near Earth's surface, whatever its mass, when air resistance is small. On the Moon it is 1.62 m/s². After 3 s of falling from rest on Earth, the velocity is 29.43 m/s.