Every mass pulls on every other mass. Newton's law of universal gravitation gives the size of that pull: F = Gm₁m₂/r², where m₁ and m₂ are the two masses in kilograms, r the distance between their centres in metres, and G the gravitational constant, 6.6743 × 10⁻¹¹ N·m²/kg². The force is in newtons and acts on both masses equally, each towards the other.
G is tiny, so the pull between everyday objects is too small to feel: two 70 kg people 1 m apart attract each other with about 3.3 × 10⁻⁷ N. It takes a planet's mass to make a force you notice. The distance is squared, which makes this an inverse square law: double the distance and the force drops to a quarter, triple it and it drops to a ninth.
The calculator solves the law for whichever of F, m₁, m₂ and r you leave blank. Masses can be given in kilograms, tonnes, Earth masses (M⊕ = 5.9722 × 10²⁴ kg) or solar masses (M☉ = 1.98847 × 10³⁰ kg), and distances in metres, kilometres or astronomical units (1 AU = 1.495978707 × 10¹¹ m). Each is converted to SI first, as its own step, so you can type 1 Earth mass and 6371 km instead of the powers of ten.
What to notice
F = Gm₁m₂/r² gives newtons only when the masses are in kilograms and r in metres. G = 6.6743 × 10⁻¹¹ N·m²/kg² is the same everywhere in the universe.
r is measured from centre to centre. For a person on the ground it is the Earth's radius, about 6371 km, not zero.
It is an inverse square law: twice as far apart means a quarter of the force, ten times as far a hundredth.
The force is the same size on both masses. The Earth pulls you with 687 N and you pull the Earth with 687 N; the Earth is just far harder to move.
At the Earth's surface the law gives the same answer as weight, W = mg: G times the Earth's mass over its radius squared is about 9.8 m/s².
Going backwards to the distance takes a square root: r = √(Gm₁m₂/F).
How to calculate gravitational force
1
Put both masses in kilograms
One Earth mass is 5.9722 × 10²⁴ kg, one solar mass 1.98847 × 10³⁰ kg, one tonne 1000 kg. In the calculator you can choose these units instead.
2
Find the distance between the centres, in metres
Kilometres multiply by 1000; 1 AU is 1.495978707 × 10¹¹ m. For an object on a planet's surface, use the planet's radius; above it, add the height to the radius.
3
Square the distance, then divide
F = G · m₁ · m₂ / r². Multiply G by both masses, then divide by r². For the Earth and a 70 kg person: 6.6743 × 10⁻¹¹ · 5.9722 × 10²⁴ · 70 / (6.371 × 10⁶)² = 687 N.
4
Read the answer in newtons
Very large or very small forces come out in powers of ten. The pull between the Sun and the Earth is about 3.54 × 10²² N.
Gravitational pull between real pairs
Values from F = Gm₁m₂/r² with G = 6.6743 × 10⁻¹¹ N·m²/kg², rounded. Each distance is centre to centre; the person is 70 kg.
Pair
Masses
Distance r
Force
Two 1 kg masses
1 kg and 1 kg
1 m
6.67 × 10⁻¹¹ N
Two people
70 kg and 70 kg
1 m
3.27 × 10⁻⁷ N
Person and the Moon overhead
70 kg and 7.342 × 10²² kg
378,029 km
0.0024 N
Person and the Sun
70 kg and 1 M☉
1 AU
0.415 N
Person and the Earth, on the ground
70 kg and 1 M⊕
6,371 km
687 N
Person and the Earth, at the height of the ISS
70 kg and 1 M⊕
6,771 km
609 N
Earth and the Moon
1 M⊕ and 7.342 × 10²² kg
384,400 km
1.98 × 10²⁰ N
Sun and the Earth
1 M☉ and 1 M⊕
1 AU
3.54 × 10²² N
Worked examples
The Earth pulling on a person
plain
m₁ = 1 M⊕, m₂ = 70 kg, r = 6371 km
Convert first: 1 M⊕ = 5.9722 × 10²⁴ kg and 6371 km = 6.371 × 10⁶ m. F = 6.6743 × 10⁻¹¹ · 5.9722 × 10²⁴ · 70 / (6.371 × 10⁶)² = 687 N. That is the person's weight: 70 · 9.81 = 686.7 N, the same within rounding.
The Earth and the Moon
plain
m₁ = 1 M⊕, m₂ = 7.342 × 10²² kg, r = 384,400 km
With r = 3.844 × 10⁸ m, F = 6.6743 × 10⁻¹¹ · 5.9722 × 10²⁴ · 7.342 × 10²² / (3.844 × 10⁸)² = 1.98 × 10²⁰ N. This pull keeps the Moon in its orbit and the Moon's pull on the Earth, the same size, raises the tides.
The Sun and the Earth
plain
m₁ = 1 M☉, m₂ = 1 M⊕, r = 1 AU
1 M☉ = 1.98847 × 10³⁰ kg and 1 AU = 1.495978707 × 10¹¹ m. F = 6.6743 × 10⁻¹¹ · 1.98847 × 10³⁰ · 5.9722 × 10²⁴ / (1.496 × 10¹¹)² = 3.54 × 10²² N.
Twice as far from the centre
plain
m₁ = 1 M⊕, m₂ = 70 kg, F = 171.86 N
Leave r blank. r = √(Gm₁m₂/F) = √(6.6743 × 10⁻¹¹ · 5.9722 × 10²⁴ · 70 / 171.86) = 1.274 × 10⁷ m, about 12,742 km: two Earth radii. A quarter of the 687 N pull at the surface, at twice the distance from the centre.
Two people 1 m apart
plain
m₁ = 70 kg, m₂ = 70 kg, r = 1 m
F = 6.6743 × 10⁻¹¹ · 70 · 70 / 1² = 3.27 × 10⁻⁷ N, the weight of a speck of dust of about 0.03 mg. Gravity between ordinary objects is real but far too weak to notice.
Common mistakes
Measuring r from the surface instead of the centre. A satellite 400 km up is 6371 + 400 = 6771 km from the Earth's centre, and that is the r to use.
Forgetting to square the distance. Dividing by r instead of r² gives an answer millions of times too big for anything planet sized.
Using kilometres in the formula. G is in N·m²/kg², so r must be in metres; using km makes the force a million times too big.
Mistyping G. It is 6.6743 × 10⁻¹¹, a negative power of ten; typing it as 6.6743e11 is out by a factor of 10²².
Thinking the bigger mass feels a bigger force. Both masses feel the same force; the lighter one just accelerates more.
Confusing G with g. G is the universal constant, 6.6743 × 10⁻¹¹ N·m²/kg². g is the acceleration at one place, 9.81 m/s² at the Earth's surface.
Gravitational force FAQ
What is the formula for gravitational force?
F = Gm₁m₂/r², Newton's law of universal gravitation. m₁ and m₂ are the masses in kilograms, r the distance between their centres in metres, and G = 6.6743 × 10⁻¹¹ N·m²/kg². The force comes out in newtons.
What is the gravitational constant G?
G is the constant that sets the strength of gravity everywhere: 6.6743 × 10⁻¹¹ N·m²/kg², the CODATA value the calculator uses. It is the force in newtons between two 1 kg masses 1 m apart.
How do you find the distance from the gravitational force?
Rearrange the formula: r = √(Gm₁m₂/F). Multiply G by both masses, divide by the force, then take the square root. The answer is the distance between the centres.
How do you find a mass from the gravitational force?
Rearrange for the unknown mass: m₁ = Fr² / (Gm₂). Multiply the force by the distance squared, then divide by G times the other mass. Leave that mass's box blank and the calculator does it.
Why is r measured from the centres?
A round planet or star pulls as if all its mass sat at its centre. So for an object on or above the Earth, r is the Earth's radius, 6371 km, plus the height above the ground.
What is the inverse square law?
The force falls with the square of the distance, because r is squared in the formula. Double the distance and the force is a quarter; triple it and the force is a ninth.
Is gravitational force the same as weight?
Yes, your weight is the Earth's gravitational force on you. Near the surface it is simpler to use W = mg, which gives the same answer: 70 kg times 9.81 m/s² is 687 N, as is G times the Earth's mass times 70 kg over the radius squared.
Why don't we feel the pull between everyday objects?
Because G is so small. Two 70 kg people 1 m apart pull on each other with about 3.3 × 10⁻⁷ N. A mass as large as a planet is needed to produce a force big enough to feel.