Accelerating a car
m = 1200 kg, a = 3 m/s²F = ma = 1200 · 3 = 3600 N, which is 3.6 kN. This is the net force: the engine has to push that much harder than the drag and friction holding the car back.
Newton's second law, F = ma, and weight, W = mg, solved for any value.
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The Coddy physics course teaches the method: you solve each problem in steps on an interactive board, and it tells you which step went wrong.
Newton's second law says the net force on an object equals its mass times its acceleration: F = ma. With m in kilograms and a in metres per second squared, F comes out in newtons, N. One newton is the force that gives 1 kg an acceleration of 1 m/s². Accelerating a 1200 kg car at 3 m/s² takes 1200 · 3 = 3600 N.
Weight is a force too, the pull of gravity on a mass, and it follows the same law with the acceleration of free fall: W = mg. On Earth g is 9.81 m/s², so a 70 kg person weighs 70 · 9.81 = 686.7 N. On the Moon g is 1.62 m/s² and the same person weighs 113.4 N. The mass stays 70 kg everywhere; only the weight changes.
The calculator has a tab for each. In the first, give two of force, mass and acceleration and it finds the third. In the second, give a mass for the weight, or a weight for the mass; g starts at 9.81 m/s² and you can change it for the Moon, another planet or a problem that uses 9.8, or clear it to find g from a weight and a mass. Grams, pounds, kilonewtons and pounds of force are converted to SI units first, and every step is shown.
Grams divide by 1000, pounds multiply by 0.4536. 500 g is 0.5 kg.
ft/s² multiply by 0.3048. For a weight, the acceleration is g: 9.81 m/s² on Earth.
F = m · a. 1200 kg · 3 m/s² = 3600 N, which is 3.6 kN.
m = F/a and a = F/m. Leave blank the box you want and the calculator writes the rearranged formula before it puts the numbers in.
W = mg with each world's surface gravity, rounded. The mass is 70 kg in every row; only g changes.
| Place | g | Weight |
|---|---|---|
| Moon | 1.62 m/s² | 113.4 N |
| Mars | 3.71 m/s² | 259.7 N |
| Venus | 8.87 m/s² | 620.9 N |
| Earth | 9.81 m/s² | 686.7 N |
| Jupiter | 24.79 m/s² | 1,735.3 N |
m = 1200 kg, a = 3 m/s²F = ma = 1200 · 3 = 3600 N, which is 3.6 kN. This is the net force: the engine has to push that much harder than the drag and friction holding the car back.
F = 20 N, a = 4 m/s²Leave the mass blank: m = F/a = 20 / 4 = 5 kg.
m = 70 kg, g = 9.81 m/s²In the weight tab, W = mg = 70 · 9.81 = 686.7 N, about 154.4 pounds of force.
m = 70 kg, g = 1.62 m/s²Change g to 1.62: W = 70 · 1.62 = 113.4 N, about a sixth of the weight on Earth, with the same 70 kg of mass.
F = ma, Newton's second law: force equals mass times acceleration. With the mass in kilograms and the acceleration in m/s², the force is in newtons. 1200 kg at 3 m/s² needs 3600 N.
The net force on an object equals its mass times its acceleration, F = ma. A bigger force gives a bigger acceleration, and a bigger mass needs a bigger force for the same acceleration.
Multiply by g, the acceleration of free fall: W = mg. On Earth g is 9.81 m/s², so 70 kg weighs 70 · 9.81 = 686.7 N. The answer is a force, in newtons.
Mass is the amount of matter in an object, in kilograms, and it does not change from place to place. Weight is the force of gravity on that mass, in newtons, so it changes with g: 686.7 N on Earth and 113.4 N on the Moon for the same 70 kg.
The SI unit of force: 1 N = 1 kg·m/s², the force that gives 1 kg an acceleration of 1 m/s². 1 kN is 1000 N, and 1 pound of force is about 4.448 N.
Rearrange F = ma to m = F/a. A force of 20 N that gives an acceleration of 4 m/s² means a mass of 20 / 4 = 5 kg.
About 1.62 m/s² on the Moon, 3.71 on Mars, 8.87 on Venus and 24.79 on Jupiter, against 9.81 on Earth. Type any of them into the g box in the weight tab.