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Rewriting the Base

Part of the Exponentials, Logs & Sequences section of Coddy's Algebra 2 journey. Lesson 9 of 46.

In 27x=81{27}^{x} = 81, 81 is not a power of 27. But 27 and 81 are both powers of 3: 27=3327 = {3}^{3} and 81=3481 = {3}^{4}. Rewrite both sides with base 3 and the equation becomes one you can match.

Writing 27 as 33{3}^{3} turns 27x{27}^{x} into (33)x{\left({3}^{3}\right)}^{x}, and a power of a power multiplies the exponents: that is 33x{3}^{3x}. So the equation reads 33x=34{3}^{3x} = {3}^{4}. Equating the exponents gives 3x=43x = 4, and x=43x = \frac{4}{3}. The answer does not have to be a whole number: a fraction is fine.

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Challenge

Solve 4x=8{4}^{x} = 8. 4 and 8 are both powers of 2: write each side as a power of 2, then set the exponents equal.

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4x=84^{x} = 8

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