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The Quotient Rule

Part of the Exponentials, Logs & Sequences section of Coddy's Algebra 2 journey. Lesson 19 of 46.

Take log⁡2(644)\log_{2}\left(\frac{64}{4}\right). Since 64=2664 = {2}^{6} and 4=224 = {2}^{2}, the quotient is 24{2}^{4}: exponents subtract when powers divide. So the log is 4, which is 6 minus 2, the log of the top minus the log of the bottom. That is the quotient rule:

log⁡b(MN)=log⁡b(M)−log⁡b(N)\log_{b}\left(\frac{M}{N}\right) = \log_{b}\left(M\right)-\log_{b}\left(N\right)

It holds for positive M and N, and the reason is the same as for the product rule. If M is b to the power p and N is b to the power q, then M over N is b to the power p minus q. The order matters: the top's log comes first, the bottom's log is taken away.

With a positive letter on top: log⁡2(x16)\log_{2}\left(\frac{x}{16}\right) becomes log⁡2(x)−log⁡2(16)\log_{2}\left(x\right)-\log_{2}\left(16\right), and log⁡2(16)\log_{2}\left(16\right) is 4, so it is log⁡2(x)−4\log_{2}\left(x\right)-4. Do not divide the logs: the log of a quotient is a difference of logs, not a quotient of logs.

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Challenge

Rewrite log⁡3(x9)\log_{3}\left(\frac{x}{9}\right) with the quotient rule. Type each line in the box under the problem: first the difference of two logs, then with the number's log worked out. You are done when it reads log⁡3(x)\log_{3}\left(x\right) minus a whole number.

Try it yourself

log⁡3(x9)\log_{3}\left(\frac{x}{9}\right)

Rewrite as log⁡3(x)−2\log_{3}\left(x\right)-2

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