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The Power Rule

Part of the Exponentials, Logs & Sequences section of Coddy's Algebra 2 journey. Lesson 20 of 46.

Take log⁡2(82)\log_{2}\left(8^{2}\right). Since 8=238 = {2}^{3}, the power is (23)2{\left({2}^{3}\right)}^{2}, which is 26{2}^{6}: a power of a power multiplies the exponents. So the log is 6, which is 2 times 3, the exponent times the log of 8. That is the power rule:

log⁡b(Mk)=klog⁡b(M)\log_{b}\left(M^{k}\right) = k\log_{b}\left(M\right)

It holds for positive M, and the exponent comes down in front of the log. The reason: if M is b to the power p, then M to the power k is b to the power kp. You can also see it as the product rule repeated: log⁡b(M3)\log_{b}\left(M^{3}\right) is the log of M times M times M, which is three logs of M added.

With a letter, watch the sign. For x > 0, log⁡3(x4)\log_{3}\left(x^{4}\right) becomes 4log⁡3(x)4\log_{3}\left(x\right). At x = -1 the left side is log⁡3(1)\log_{3}\left(1\right), which is 0, but log⁡3(−1)\log_{3}\left(-1\right) has no value, so the rule needs x positive. The rule works in every base, base 10 included.

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Challenge

For positive x, rewrite log⁡(x5)\log\left({x}^{5}\right) with the power rule. Type the result in the box under the problem, then press Check.

Try it yourself

log⁡(x5)\log\left(x^{5}\right)

Rewrite as 5log⁡(x)5\log\left(x\right)

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