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A Ladder and a Secant

Part of the Right-Triangle Trigonometry section of Coddy's Trigonometry journey. Lesson 39 of 46.

A reciprocal ratio often states a comparison directly. A rope that is twice as long as its peg is far from the mast has hypotenuse over adjacent equal to 2, which is sec θ = 2, so cos θ = 1/2 and the rope stands at 60° to the ground.

Off the special values the flip works the same way. If a cable is 1.5 times as long as the distance from its anchor to the pole, sec⁡(θ)=1.5\sec\left(\theta\right) = 1.5, so cos θ = 1/1.5 = 2/3 and θ = arccos(2/3), about 48.19°. On the board, Use arcsec: every angle in the domain writes θ = arcsec(1.5) and the round chip finishes it.

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Challenge

A ladder is 2.5 times as long as the distance from its foot to the wall, so the angle θ it makes with the ground has sec θ = 2.5. Find θ in degrees, to two decimal places. Then press Check.

Try it yourself

sec⁡θ=2.5\sec {\theta} = 2.5

Get θ{\theta} alone0∘<θ<90∘0^{\circ} < {\theta} < 90^{\circ}

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