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Multiplying Functions

Part of the Functions & Transformations section of Coddy's Algebra 2 journey. Lesson 18 of 58.

Multiplying functions multiplies their outputs. For p(x) = x + 4 and q(x) = x - 1, using both rules turns p(x) × q(x) into (x + 4)(x - 1). Each rule gets its own brackets, because the whole output of p multiplies the whole output of q.

Then multiply out as in Algebra: every term of the first bracket times every term of the second. That gives x^2 - x + 4x - 4, and collecting leaves x^2 + 3x - 4.

Without the brackets, x + 4x - 1 would multiply only the 4 by x, which is a different function. Check with x = 2: p(2) is 6 and q(2) is 1, so the product is 6, and 4 + 6 - 4 is 6 as well.

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Challenge

For f(x) = x + 3 and g(x) = x - 2, find f(x) × g(x), multiplied out and collected.

Try it yourself

f(x) * g(x)

Multiply everything out

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