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Solving f(x) = k

Part of the Functions & Transformations section of Coddy's Algebra 2 journey. Lesson 4 of 55.

So far you put an input into a function and got the output. Solving goes the other way. You know the output, and you look for the input.

For f(x)=x2−1f\left(x\right) = {x}^{2}-1 and the output 3, write the rule equal to 3: x2−1=3{x}^{2}-1 = 3. Add 1 to both sides: x2=4{x}^{2} = 4. So x = 2 or x = -2. The curve meets the line y = 3 two times.

The curve y = x squared minus 1 crossing the dashed line y = 3 at x = -2 and x = 2

Two inputs can have the same output. That is fine for a function. But one input can never have two outputs. On a graph, a vertical line never crosses a function two times. So a circle is not a function.

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Challenge

For f(x)=x2−7f\left(x\right) = {x}^{2}-7, which inputs give the output 9? Find all of them. Open the graph on the paper to see the curve meet the line y = 9.

Try it yourself

f(x)=9f\left(x\right) = 9

Get xx alone

Givenf(x)=x2−7f\left(x\right) = x^{2}-7

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