Menu

Taller and Flatter

Part of the Functions & Transformations section of Coddy's Algebra 2 journey. Lesson 36 of 55.

A number that multiplies the whole function changes heights, not positions. Take y=3f(x)y = 3f\left(x\right) with f(x)=x2f\left(x\right) = {x}^{2}. Every output of f is tripled. The vertex (0, 0) stays put, because 3 times 0 is 0. But one step to the right, where f gives 1, the new graph gives 3: the point (1, 1) becomes (1, 3).

The parabola y = x^2 dashed, and a narrower parabola through (1, 3)

Tripling every height makes the curve climb three times as fast.

So the curve is narrower. A factor between 0 and 1 does the opposite: y=12f(x)y = \frac{1}{2}f\left(x\right) halves every height, and one step from the vertex it has risen only 1/2, so it looks flatter.

So two points fix the curve: the vertex says where it sits, and the point one step to its right says how fast it climbs. On y=af(x)y = af\left(x\right), that point is a above the vertex instead of 1.

challenge icon

Challenge

Draw the graph of y=2f(x)y = 2f\left(x\right) for f(x)=x2f\left(x\right) = {x}^{2}. The faint curve is f itself. Place the vertex, then drag the second point.

Try it yourself

y=2f(x)y = 2f\left(x\right)

Draw the parabola

quiz iconTest yourself

This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Functions & Transformations