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A Missing Term

Part of the Polynomials & Rational Expressions section of Coddy's Algebra 2 journey. Lesson 4 of 54.

Long division lines up like terms, the way number division lines up hundreds, tens and ones. In 407 the 0 holds the tens place. In x^3 - 7x + 6 there is no x^2 term, so hold its place with a zero:

x^3 + 0x^2 - 7x + 6

Now divide by x + 3. First round: x^3 over x is x^2, and x^2(x + 3) is x^3 + 3x^2. Subtract from x^3 + 0x^2: -3x^2 is left, and bring down the minus 7x. Second round: -3x(x + 3) is -3x^2 - 9x, and subtracting leaves 2x + 6. Third round: 2(x + 3) is exactly 2x + 6, so

(x^3 - 7x + 6)/(x + 3) = x^2 - 3x + 2

Without the placeholder, the 3x^2 of the first product would sit under the minus 7x, and unlike terms cannot be taken from each other.

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Challenge

Divide x^3 - 8 by x - 2. The top has no x^2 or x term: think of them as 0x^2 and 0x.

Try it yourself

(x^3 - 8)/(x - 2)

Divide the polynomials

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

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