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Factor the Bottoms First

Part of the Polynomials & Rational Expressions section of Coddy's Algebra 2 journey. Lesson 35 of 54.

Take 2/(x^2 - 25) + 1/(x - 5). Multiplying the bottoms would give a cubic, far more than you need. Factor first: x^2 - 25 = (x + 5)(x - 5). Now you can see that the second bottom, x - 5, is already inside the first.

So the least common denominator is just (x + 5)(x - 5). The first fraction already has it, and the second is only missing x + 5:

2/((x + 5)(x - 5)) + (x + 5)/((x + 5)(x - 5))

Why factor? A common denominator is built from factors: every factor of every bottom must be in it, and nothing more. Shared factors only show once the bottoms are factored. Adding the tops gives (x + 7)/((x + 5)(x - 5)).

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Challenge

Add 3/(x^2 - 4) + 1/(x + 2) and write the sum as one fraction. Factor the first bottom before anything else.

Try it yourself

3/(x^2 - 4) + 1/(x + 2)

Write it as one fraction

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

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