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Cross-Multiplying

Part of the Polynomials & Rational Expressions section of Coddy's Algebra 2 journey. Lesson 36 of 51.

When each side is a single fraction, there is a shortcut. In 4x+2=3x−1\frac{4}{x+2} = \frac{3}{x-1}, multiply each top by the other side's bottom and set the products equal. This is cross multiplying:

4(x−1)=3(x+2)4\left(x-1\right) = 3\left(x+2\right)

Why does it work? It is the same as multiplying both sides by both bottoms, (x+2)(x−1)\left(x+2\right)\left(x-1\right). On each side one bottom cancels and the other stays, landing next to the opposite top. It only works when each side is one fraction: 1x+2=3x\frac{1}{x}+2 = \frac{3}{x} has two terms on the left, so you clear it the long way.

From there it is linear: 4x−4=3x+64x-4 = 3x+6, so x is 10. The bottoms held x, so check it: at 10 neither x+2x+2 nor x−1x-1 is 0, and both sides are 1/3.

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Challenge

Solve 3x+1=2x−1\frac{3}{x+1} = \frac{2}{x-1}, then check your answer.

Try it yourself

3x+1=2x−1\frac{3}{x+1} = \frac{2}{x-1}

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