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The Perpendicular Bisector

Part of the Congruence & Proof section of Coddy's Geometry journey. Lesson 50 of 63.

The perpendicular bisector of a segment is the line through its midpoint at right angles to it. Every point on it is the same distance from both ends of the segment. Proving that uses two definitions at once: the Definition of midpoint gives equal halves, and the Definition of perpendicular turns perpendicular lines into right angles.

Segment AB with D between A and B, and C above D joined to A, D and B

StatementReason
1. CD ⊥ ABGiven
2. ∠CDA is a right angleDefinition of perpendicular, using line 1
3. ∠CDB is a right angleDefinition of perpendicular, using line 1

Here CD ⊥ AB, and the definition turns that one fact into two right angles at D, one line for each. To prove the theorem you will combine those right angles with the midpoint's halves and the side the two triangles share. The proof is long, but each step is a reason you already know.

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Challenge

You are given that S is the midpoint of PQ and that RS ⊥ PQ. Prove that RP = RQ, then press Check.

Try it yourself

Write the proof

Write the proof

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

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