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Final: Master of Triangles

Part of the Triangles section of Coddy's Geometry journey. Lesson 71 of 71.

To find the area of an isosceles triangle, first find its height with the Pythagorean theorem. The equal side is the hypotenuse and half the base is one leg. Then put that height and the whole base into the area formula, half the base times the height. Work out the squares first, then the square root, and finally the product. For example, an isosceles triangle with equal sides 5 and base 6 has height √(5^2 - 3^2) = 4 and area 1/2 × 6 × 4 = 12. Half the base, 3, goes under the root, and the whole base, 6, goes in the area formula.

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Challenge

An isosceles triangle has equal sides 13 and base 24. Its height is the root of 13^2 - 12^2.

An isosceles triangle with equal sides 13, base 24 and a dashed height h splitting the base into halves of 12

Find its area A.

Try it yourself

A = 1/2 * 24 * sqrt(13^2 - 12^2)

Solve for A

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Triangles