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Reciprocals in Radians

Part of the Angles and the Unit Circle section of Coddy's Trigonometry journey. Lesson 48 of 55.

Radians change nothing. Take csc⁡(7π4)\csc\left(\frac{7\pi}{4}\right): 2π − π/4, quadrant IV, reference π/4. Sine is negative there, so csc⁡(7π4)=−csc⁡(π4)\csc\left(\frac{7\pi}{4}\right) = -\csc\left(\frac{\pi}{4}\right), and sin(π/4) = √2/2 flips to 2/√2 = √2. The value is −√2.

Cotangent flips tangent: cot(π/6) is 1/(√3/3), which is √3, and cot(π/4) is 1. Where tangent is undefined, at π/2, cotangent is 0, because cos/sin is 0/1 there.

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Challenge

Work out cot⁡(2π3)\cot\left(\frac{2\pi}{3}\right) exactly, then press Check.

Try it yourself

cot⁡(2π3)\cot\left(\frac{2\pi}{3}\right)

Simplify

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