The 30° and 60° Points
Part of the Angles and the Unit Circle section of Coddy's Trigonometry journey. Lesson 26 of 57.
Half an equilateral triangle is a 30-60-90 triangle. With hypotenuse 1, the side opposite 30° is half of it, 1/2, and Pythagoras gives the other leg: √(1 - 1/4) = √(3)/2.
At 30° the long leg is the across and the short leg the height, so the point is (√(3)/2, 1/2): cos(30°) = √(3)/2 and sin(30°) = 1/2.
Stand the same triangle on its other end and the 60° angle is at the centre. Which leg is which is then the whole question: the leg opposite the angle at the centre is the height.
Challenge
Set the coordinates of the point at 60°, then press Check.
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Angles and the Unit Circle
1A Point on a Circle
Height on the CircleAcross: the CosineSame Height, Two AnglesRecap: Height and Across4Radians
What a Radian IsDegrees to RadiansRadians to DegreesRadians Without πTurns in RadiansRecap: Radians5Arc Length and Sector Area
Arc LengthArcs From DegreesFinding the AngleSector AreaRecap: A Slice of Pizza3Coterminal Angles
Coterminal AnglesBack Into One TurnValues Repeat Every TurnEvery Turn at OnceRecap: Coterminal Angles6The Unit Circle
Why (cos θ, sin θ)The 30° and 60° PointsThe 45° PointPoints Off the TableRecap: Quadrant I Points