The 45° Point
Part of the Angles and the Unit Circle section of Coddy's Trigonometry journey. Lesson 27 of 57.
At 45° the triangle under the point has two 45° angles, so its legs are equal. Call each a. Pythagoras with hypotenuse 1: a^2 + a^2 = 1, so a^2 = 1/2 and a = √(2)/2, about 0.71.
So the point at 45° is (√(2)/2, √(2)/2): across and height are equal, which is the only place in quadrant I where that happens. The three special points of quadrant I use just three sizes: 1/2, √2/2 and √3/2.
Challenge
Tap every angle in one turn where the height is √(2)/2. Then press Check.
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Angles and the Unit Circle
1A Point on a Circle
Height on the CircleAcross: the CosineSame Height, Two AnglesRecap: Height and Across4Radians
What a Radian IsDegrees to RadiansRadians to DegreesRadians Without πTurns in RadiansRecap: Radians5Arc Length and Sector Area
Arc LengthArcs From DegreesFinding the AngleSector AreaRecap: A Slice of Pizza3Coterminal Angles
Coterminal AnglesBack Into One TurnValues Repeat Every TurnEvery Turn at OnceRecap: Coterminal Angles6The Unit Circle
Why (cos θ, sin θ)The 30° and 60° PointsThe 45° PointPoints Off the TableRecap: Quadrant I Points