CSRF and APIs
Part of the JSON APIs section of Coddy's Django journey. Lesson 6 of 19.
A real program that sends POST /api/tasks/ gets 403 Forbidden. Django's CSRF protection wants every POST to carry a secret token from one of your own pages, so another website cannot make a visitor's browser submit your forms. A program has no such page and no token.
@csrf_exempt, from django.views.decorators.csrf, turns the check off for one view:
@csrf_exempt
def webhook(request):
...That gives something up: any website can now make a visitor's browser send this POST. It is fine for a view that does not depend on who is logged in, like the task list. An API that acts as the logged-in user keeps CSRF on, and its page's script sends the token in an X-CSRFToken header.
Challenge
MediumLet programs without a CSRF token create tasks:
POST /api/tasks/works with no token.- Only
task_listis exempt.
Press Run, then type this in the Shell tab. Before the change it prints 403, after it 201: from django.test import Client; print(Client(enforce_csrf_checks=True).post("/api/tasks/", {"title": "Pay rent"}, content_type="application/json").status_code)
Try it yourself
import json
from django.http import JsonResponse
from django.shortcuts import render
from .models import Task
def task_to_dict(task):
return {
"id": task.id,
"title": task.title,
"done": task.done,
"priority": task.priority,
}
def home(request):
return render(request, "tasks/home.html", {"tasks": Task.objects.all()})
def stats(request):
data = {
"total": Task.objects.count(),
"done": Task.objects.filter(done=True).count(),
}
return JsonResponse(data)
def task_list(request):
if request.method == "POST":
data = json.loads(request.body)
task = Task.objects.create(
title=data["title"],
priority=data.get("priority", "normal"),
)
return JsonResponse(task_to_dict(task), status=201)
tasks = Task.objects.all()
done = request.GET.get("done")
if done == "true":
tasks = tasks.filter(done=True)
elif done == "false":
tasks = tasks.filter(done=False)
return JsonResponse([task_to_dict(task) for task in tasks], safe=False)
def task_detail(request, pk):
task = Task.objects.filter(pk=pk).first()
if task is None:
return JsonResponse({"error": "Task not found"}, status=404)
return JsonResponse(task_to_dict(task))
All lessons in JSON APIs
2Reading Requests
Filter with a QueryCreating with POSTPractice on your own: Django playground